180onwarding
发贴: 19
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于 2006-04-28 11:06
我的jsp配置环境apache:apache_1.3.34-win32-x86-no_src,mod_jk_1.2.6_2.0.50 j2sdk:j2sdk-1_4_2_11-windows-i586-p tomcat:jakarta-tomcat-4.1.31-LE-jdk14 WIN:win2000 下面是我的一段.java程序: package MyPackage;
import java.io.*; import javax.servlet.*; import javax.servlet.http.*; import java.util.*;
public class ShowParameters extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); String title = "读取所有请求参数"; out.println(ServletUtilities.headWithTitle(title) + "<BODY BGCOLOR=\"#FDF536\">\n"+ "<H1 ALIGN=CENTER>"+title + "</H1>\n" + "<TABLE BORDER=1 ALIGN=CENTER>\n" + "<TR BGCOLOR=\"#FFAD00\">\n" + "<TH>参数名字<TH>参数值"); Enumeration paramNames = request.getParameterNames(); while(paramNames.hasMoreElements()) { String paramName = (String)paramNames.nextElement(); out.println("<TR><TD>" + paramName + "\n<TD>"); String[] paramValues = request.getParameterValues(paramName); if (paramValues.length == 1) { String paramValue = paramValues[0]; if (paramValue.length() == 0) out.print("<I>No Value</I>"); else out.print(paramValue); } else { out.println("<UL>"); for(int i=0; i<paramValues.length; i++) { out.println("<LI>" + paramValues[i]); } out.println("</UL>"); } } out.println("</TABLE>\n</BODY></HTML>"); }
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { doGet(request, response); } } 错误提示信息如下: ShowParameters.java:4:package javax.servlet does not exist import javax.servlet.http.*; ShowParameters.java:8:cannot resolve symbol symbol:class HttpServlet location:class MyPackage.ShowParameters public class ShowParameters extends HttpServlet{ ^ ShowParameters.java:9:cannot resolve symbol symbol:class HttpServletRequest location:class MyPackage.ShowParameters public void doGet<HttpServletRequest request, ^ ShowParameters.java:10:cannot resolve symbol symbol:class HttpServletResponse location:class MyPackage.ShowParameters HttpServletResponse> ^ 下面也是同以上一样的提示信息,能帮忙看一下什么地方的原因吗?
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