Java开发网 - 关于SERVLET

Topic: 关于SERVLET

1.关于SERVLET

Posted by: panjiandong
Posted on: 2004-04-16 13:06

package sevlet1;

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;

public class Servlet1 extends HttpServlet {
private static final String CONTENT_TYPE = "text/html; charset=GBK";
/**Initialize global variables*/
public void init() throws ServletException {
}
/**Process the HTTP Post request*/
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType(CONTENT_TYPE);
PrintWriter out = response.getWriter();
out.println("<html>");
out.println("<head><title>Servlet1</title></head>");
out.println("<body>");
out.println("<p>The servlet has received a POST. This is the reply.</p>");
Enumeration e=request.getParameterNames();
while(e.hasMoreElements())
{
String name=(String)e.nextElement();
String value=request.getParameter(name);
out.println(name+"==="+value);
}
out.println("</body></html>");
}
/**Clean up resources*/
public void destroy() {
}
}
高手帮我看看是什么错误
谢谢！！！！！

2.Re:关于SERVLET [Re: panjiandong]	Copy to clipboard
Posted by: zerol Posted on: 2004-04-16 15:15 ask smart , please ! 同学,信息详细一点!

3.Re:关于SERVLET [Re: panjiandong]	Copy to clipboard
Posted by: panjiandong Posted on: 2004-04-16 17:02 我在DOS 下面运行上面的代码报错有几十外的错误是不是我的SERVLET 配置有问题的咧？？？

4.Re:关于SERVLET [Re: panjiandong]	Copy to clipboard
Posted by: tiengulden Posted on: 2004-04-17 15:47 把dos下报的异常贴出来。

5.Re:关于SERVLET [Re: tiengulden]	Copy to clipboard
Posted by: nothing Posted on: 2004-04-17 16:58 servlet 要在tomcat一类的应用服务器上运行

6.Re:关于SERVLET [Re: panjiandong]

Copy to clipboard

Posted by: nothing
Posted on: 2004-04-17 17:11



package untitled1;

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;

public class Servlet1
    extends HttpServlet {
  private static final String CONTENT_TYPE = "text/html; charset=GBK";
  /**Initialize global variables*/
  public void init() throws ServletException {
  }

  /**Process the HTTP Post request*/
  public void doGet(HttpServletRequest request, HttpServletResponse response) throws
      ServletException, IOException {
    response.setContentType(CONTENT_TYPE);
    PrintWriter out = response.getWriter();
    out.println("<html>");
    out.println("<head><title>Servlet1</title></head>");
    out.println("<body>");
    out.println("<p>The servlet has received a POST. This is the reply.</p>");
    Enumeration e = request.getHeaderNames();
    while (e.hasMoreElements()) {
      String name = (String) e.nextElement();
      String value = request.getParameter(name);
      out.println(name + "===" + value + "<BR>");
    }
    out.println("</body></html>");
  }

  public void doPost(HttpServletRequest request, HttpServletResponse response) throws
      ServletException, IOException {
    doGet(request, response);
  }

  /**Clean up resources*/
  public void destroy() {
  }
}

7.Re:关于SERVLET [Re: panjiandong]	Copy to clipboard
Posted by: panjiandong Posted on: 2004-04-17 18:24 感谢各位高手！！！！！