Topic: 大家能用编这个小程序吗? |
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1.大家能用编这个小程序吗? | Copy to clipboard |
Posted by: smwyzy Posted on: 2008-10-19 21:13 x+y+z=100 3x+5y+0.5z=100 能编个能解这方程组的程序吗?让我学习学习; |
2.Re:大家能用编这个小程序吗? [Re: smwyzy] | Copy to clipboard |
Posted by: micsolaris Posted on: 2008-10-20 02:20 你给的这两个式子要求的解应该是不存在的吧?三元函数好像代表的是一个三维图中的面吧,两个面相交的话是一条线,所以解应该有无数个。除非你要的是如下的做法。(取一段范围的数 x (1-100) y (1-100)) package com.ricky.www; |
3.Re:大家能用编这个小程序吗? [Re: smwyzy] | Copy to clipboard |
Posted by: smwyzy Posted on: 2008-10-21 21:37 多谢,漏了个条件:x,y,z必须都是整数。 |
4.Re:大家能用编这个小程序吗? [Re: smwyzy] | Copy to clipboard |
Posted by: gbluo Posted on: 2008-10-29 11:41 我在想x,y和z能不能取负值....... 要是能取负值的话,一楼的程序应该有问题,要是不能的话,只要: package com.ricky.www; public class Test { public static void main(String args[]) { int z = 0; for(int x = 0 ; x < 34 ; x ++) { for(int y = 0 ; y < 21 ; y ++) { z = 100 - x - y; if((3 * x + 5 * y + 0.5 * z) == 100) { System.out.println("当x = " + x + " y = " + y + " z = " + z + "时候等式成立."); } } } } } 就可以,不过可惜,这个程序我也没有运行出结果来,大家帮忙看一下. |
5.Re:大家能用编这个小程序吗? [Re: smwyzy] | Copy to clipboard |
Posted by: floater Posted on: 2008-10-30 02:16 no solution since you have that 0.5 coefficient there. |
6.Re:大家能用编这个小程序吗? [Re: smwyzy] | Copy to clipboard |
Posted by: zyj0021 Posted on: 2008-10-30 23:44 得,回去看下线性代数!! 数学的东东忘的差不多了!!!!! |
7.Re:大家能用编这个小程序吗? [Re: smwyzy] | Copy to clipboard |
Posted by: JiafanZhou Posted on: 2008-11-10 20:31 IMHO, I don't think we can work out this simultaneous equation by only two equations. As far as I can remember, my maths teacher in the senior high school mentioned we need at least three non-redundant equations, in order to work out x, y, z. In addition, as *micsolaris* pointed out, there are three unknown variables, x, y, z. Thus it is not a linear line but a surface. Hence, these two equations represents two separate surfaces in a 3-D space. Then in this case, there are two options: 1) If they intersect, then answers: x, y , z are unlimited. 2) If they don't intersect, then answers are none. Fortunately, I think our computer can help us to solve this simultaneous equation by running the following code: (which accounts for negative numbers.)
It is important to note that this program only takes account of the Integer range which inside -2 to the power of 31 to +2 to the power of 31. Of course all computers have limited CPU, memory, resources etc... We can not run unlimited range of numeric values. Unfortunately, I have naively think about successfully running this program on my computer. The program has been running on my machine for about 3 hours and it took all my CPU utilisation. Perhaps you can use a super-computer to run this program and find out the answer. (maybe DeepBlue can help) Finally, I do believe that there are answers for this simultaneous equation. Regards, Jiafan |
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