Java开发网 - 问一个正则表达式。

Topic: 问一个正则表达式。

1.问一个正则表达式。	Copy to clipboard
Posted by: uniquejava Posted on: 2007-06-11 18:13 问一个正则表达式。怎么匹配abc后面跟任意个字符？是不是abc.* 那abc后面跟非abc这个单词的任意字符呢试了abc[^abc]*不行。因为它的意思是abc后面跟上非a或者非b或者非c

2.Re:问一个正则表达式。 [Re: uniquejava]	Copy to clipboard
Posted by: swiftybin Posted on: 2007-06-12 08:06 跟任意个字符是abc.*$ 另一个不知道，，正则不精啊！

3.Re:问一个正则表达式。 [Re: uniquejava]

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Posted by: JiafanZhou
Posted on: 2007-06-12 18:12

uniquejava wrote:
问一个正则表达式。怎么匹配abc后面跟任意个字符？

abc.*

那abc后面跟非abc这个单词的任意字符呢

abc[^abc]*

试了abc[^abc]*不行。因为它的意思是abc后面跟上非a或者非b或者非c

abc[^abc]* means a followed by b followed by c followed by any character except a, b, or c, zero or more times.
So it is right.

Regards,
Jiafan

4.Re:问一个正则表达式。 [Re: HenryShanley]

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Posted by: uniquejava
Posted on: 2007-06-13 08:28

HenryShanley wrote:
abc.*

abc[^abc]*

abc[^abc]* means a followed by b followed by c followed by any character except a, b, or c, zero or more times.
So it is right.

Regards,
Jiafan

thank you, but
you mistook my opinion, i mean i need a regular expression means " a followed by b followed by c followed by any character except the whole word 'abc'.
that is, given a regular expression, so "abcabd" can match, but "abcabc" can not match

help

5.Re:问一个正则表达式。 [Re: uniquejava]	Copy to clipboard
Posted by: livahu Posted on: 2007-06-21 09:19 package com.livahu; import java.util.regex.Pattern; public class RegTest { public static void main(String[] args) { boolean flag = Pattern.matches("\\babc(?!abc)(.(?!abc))*\\b", "abcdddadbc"); System.out.println(flag); } }

6.Re:问一个正则表达式。 [Re: uniquejava]	Copy to clipboard
Posted by: uniquejava Posted on: 2007-07-31 15:50 一个多月没来了，竟然有人搞出来了！，强！！！感谢！今天终于明白了，原来用负向前瞻（？！）就可以搞出来！

7.Re:问一个正则表达式。 [Re: uniquejava]	Copy to clipboard
Posted by: Cappuccino Posted on: 2007-08-01 01:20 test the following pattern (?<=abc).*

8.Re:问一个正则表达式。 [Re: uniquejava]	Copy to clipboard
Posted by: uniquejava Posted on: 2007-08-02 11:34 谢谢，又学了一招，用后瞻lookbehind代码确实更简洁。 boolean flag = Pattern.matches("\\babc.*(?<!abc)\\b", "abcdddadbc");