Java开发网 - 如何给变量输入数据？如C语言里的scanf

Topic: 如何给变量输入数据？如C语言里的scanf

1.如何给变量输入数据？如C语言里的scanf	Copy to clipboard
Posted by: wangchen223 Posted on: 2006-07-08 15:09 如何给变量输入数据？如C语言里的scanf

2.Re:如何给变量输入数据？如C语言里的scanf [Re: wangchen223]	Copy to clipboard
Posted by: Jcat Posted on: 2006-07-08 18:54 byte[] temp=new byte[128]; System.in.read(temp); System.out.println(new String(temp)); 我想问的是，当输入超过128个byte以后，怎么办？

3.Re:如何给变量输入数据？如C语言里的scanf [Re: wangchen223]	Copy to clipboard
Posted by: mtdhwgij Posted on: 2006-07-08 20:32 wangchen223 wrote: 如何给变量输入数据？如C语言里的scanf import javax.swing.JOptionPane; ..... ｛String m; 　m=JOptionPane.showInputDialog; ..... ｝

4.Re:如何给变量输入数据？如C语言里的scanf [Re: Jcat]	Copy to clipboard
Posted by: mtdhwgij Posted on: 2006-07-08 20:36 Jcat wrote: byte[] temp=new byte[128]; System.in.read(temp); System.out.println(new String(temp)); 我想问的是，当输入超过128个byte以后，怎么办？这个貌似要进行异常处理。

5.Re:如何给变量输入数据？如C语言里的scanf [Re: mtdhwgij]	Copy to clipboard
Posted by: sunjavaduke Posted on: 2006-07-08 21:59 mtdhwgij wrote: import javax.swing.JOptionPane; ..... ｛String m; 　m=JOptionPane.showInputDialog; ..... ｝ That will be ok! and you can use other method to transfer the format! For example,you input 25,and you want an variable of int type,so you can use: int number=Integer.parseInt(m);

6.Re:如何给变量输入数据？如C语言里的scanf [Re: wangchen223]

Copy to clipboard

Posted by: wangchen223
Posted on: 2006-07-09 15:59

public class lianxi2
{
  public static void main(String[]args)
  {
    byte[] temp=new byte[128];
    System.in.read(temp);
    System.out.println(new String(temp));
  }
}
有错误呀
C:\Downloads\gerenlianxi>javac lianxi2.java
lianxi2.java:6: unreported exception java.io.IOException; must be caught or dec
ared to be thrown
System.in.read(temp);
^
1 error
1 error

7.Re:如何给变量输入数据？如C语言里的scanf [Re: wangchen223]	Copy to clipboard
Posted by: joshuajava Posted on: 2006-07-10 00:11 引用：unreported exception java.io.IOException; must be caught or dec ared to be thrown IO流要加入异常抛出捕获的。。。。 public static void main(String[]args) { try { byte[] temp=new byte[128]; System.in.read(temp); System.out.println(new String(temp)); }catch(Exception e){ e.printstackTrace(); } }