Java开发网 - 帮忙看一下( 怎样输出下面的三角图形)

Topic: 帮忙看一下( 怎样输出下面的三角图形)

1.帮忙看一下( 怎样输出下面的三角图形)	Copy to clipboard
Posted by: manwubianji Posted on: 2006-06-17 21:35 怎样输出下面的图形 * * * * * * * * * * * * * * * * 小弟先谢谢了

2.Re:帮忙看一下 [Re: manwubianji]	Copy to clipboard
Posted by: xiaosilent Posted on: 2006-06-17 22:25 public class Demo{ public static void main(String[] args){ System.out.println(""); System.out.println(""); System.out.println("*"); System.out.println("*****"); } } 这样？

3.Re:帮忙看一下 [Re: manwubianji]	Copy to clipboard
Posted by: Skybus Posted on: 2006-06-18 00:16 好像是要求使用循环吧

4.Re:帮忙看一下( 怎样输出下面的三角图形) [Re: manwubianji]	Copy to clipboard
Posted by: hailang1986 Posted on: 2006-06-18 20:22 2楼的方法是可行的，也是最简单的。

5.Re:帮忙看一下( 怎样输出下面的三角图形) [Re: manwubianji]	Copy to clipboard
Posted by: oujianqiang Posted on: 2006-06-18 20:23 从控制台输入要打印的行数，而每一行的*怯是一个等差数列，求出通项，就可以解决了

6.Re:帮忙看一下( 怎样输出下面的三角图形) [Re: manwubianji]	Copy to clipboard
Posted by: sunjavaduke Posted on: 2006-06-19 16:59 用个循环应该就可以了二楼的效率不好

7.Re:帮忙看一下( 怎样输出下面的三角图形) [Re: sunjavaduke]

Copy to clipboard

Posted by: why
Posted on: 2006-06-20 19:40

sunjavaduke wrote:
二楼的效率不好

What did you mean?
效率好? something like
System.out.println("*\n***\n*****\n*******");
Wink

oujianqiang wrote:
从控制台输入要打印的行数，而每一行的*怯是一个等差数列，求出通项，就可以解决了

What is 怯 in 每一行的*怯是一个等差数列?

A solution for you to start with:


  void printTriangle(int numLevels) {
    for (int i = 1; i <= numLevels; i++) {
      // print the leading spaces
      for (int j = 1; j <= (numLevels - i); j++) {
        System.out.print("   ");
      }
      // print the asterisks
      for (int j = (numLevels - (i - 1)); j <= (numLevels + (i - 1)); j++) {
        System.out.print(" *");
      }
      // newline (level)
      System.out.println();
    }
  }