Java开发网 - JAVA 魂牵梦绕的一道难题

Topic: JAVA 魂牵梦绕的一道难题

1.JAVA 魂牵梦绕的一道难题

Posted by: jasonhero
Posted on: 2006-05-17 13:09

有人做了一件好事，A说不A做的，B说是C做的，C说是D做的，D说C在说谎，三人说真话，一人说假话，编程得出好事是谁做的？
算法：
A说不是A做的：0A 1BCD
B说是C做的： 1C 1C
C说是D做的： 1D 1D
D说C在说谎： 0D 1ABC
然后把它们存到一个二维数组中，查找出现三次的那个字符就是做好事的人
代码如下：
import java.io.*;
public class t
{
static String str1[]={"A","B","C","D"};
static String str2[][]={{"*","*","*","*"},{"*","*","*","*"},{"*","*","*","*"},{"*","*","*","*"}};
static int k=0;
public static void main(String args[])throws IOException
{

int bA;
String b1,b2,b3,b4,c1,c2,c3,c4;

//输入A
BufferedReader aIn=new BufferedReader(new InputStreamReader(System.in));
System.out.println("A说：");
b=aIn.readLine();
bA=Integer.parseInt Beer

;
c=aIn.readLine();
char g = c.charAt(0);
hanshu(bA,g);//函数调用

System.out.println("B说：");
b2=aIn.readLine();
bA=Integer.parseInt(b2);
c2=aIn.readLine();
char g2 = c2.charAt(0);
hanshu(bA,g2);//函数调用

System.out.println("C说：");
b3=aIn.readLine();
bA=Integer.parseInt(b3);
c3=aIn.readLine();
char g3 = c3.charAt(0);
hanshu(bA,g3);//函数调用

System.out.println("D说：");
b4=aIn.readLine();
bA=Integer.parseInt(b4);
c4=aIn.readLine();
char g4 = c4.charAt(0);
hanshu(bA,g4);//函数调用

//bA和c的输出
System.out.println(bA);
System.out.println Present

;

//数组输出
for(int i=0;i<4;i++)
System.out.print(str1+" ");
System.out.println("\n");
for(int i=0;i<4;i++)
{
System.out.println("\n");
for(int j=0;j<4;j++)
System.out.print(str2[j]+" ");
}
}
//函数
static void hanshu(int x,char y) {
String comp = "";
comp += y;
switch Fight

{
case 0:
for(int i=0;i<4;i++)
{
if(comp==str1)
str1="*";
if(comp!=str1)
str2[0][k]=str1;
k++;
}
break;

}
}

}

此代码出现几个错误，但在下苦思冥想的确是无能为力了，真诚求教高手解答，先谢过

2.Re:JAVA 魂牵梦绕的一道难题 [Re: jasonhero]	Copy to clipboard
Posted by: java学生 Posted on: 2006-05-17 21:21 恩,看不懂!

3.Re:JAVA 魂牵梦绕的一道难题 [Re: jasonhero]	Copy to clipboard
Posted by: king431 Posted on: 2006-05-19 21:43 很难明白！虽然不能帮到你，但是帮你顶一下

4.Re:JAVA 魂牵梦绕的一道难题 [Re: jasonhero]

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Posted by: oujianqiang
Posted on: 2006-05-21 10:05

已修改，看是不是你想要的结果
import java.io.*;
public class t
{
static String str1[]={"A","B","C","D"};
static String str2[][]={{"*","*","*","*"},{"*","*","*","*"},{"*","*","*","*"},{"*","*","*","*"}};
public static void main(String args[])throws IOException
{

int bA;
String b1,b2,b3,b4,c1,c2,c3,c4;

//输入A
BufferedReader aIn=new BufferedReader(new InputStreamReader(System.in));
System.out.println("A说：");
b1=aIn.readLine();
bA=Integer.parseInt(b1);
c1=aIn.readLine();
String g = c1.substring(0,0);
hanshu(bA,g);//函数调用

System.out.println("B说：");
b2=aIn.readLine();
bA=Integer.parseInt(b2);
c2=aIn.readLine();
String g2 = c2.substring(0,0);
hanshu(bA,g2);//函数调用

System.out.println("C说：");
b3=aIn.readLine();
bA=Integer.parseInt(b3);
c3=aIn.readLine();
String g3 = c3.substring(0,0);
hanshu(bA,g3);//函数调用

System.out.println("D说：");
b4=aIn.readLine();
bA=Integer.parseInt(b4);
c4=aIn.readLine();
String g4 = c4.substring(0,0);
hanshu(bA,g4);//函数调用

//bA和c的输出
System.out.println(bA);
System.out.println();

//数组输出
for(int i=0;i<4;i++)
System.out.print(str1[i]+" ");
System.out.println("\n");
for(int i=0;i<4;i++)
{
System.out.println("\n");
for(int j=0;j<4;j++)
System.out.print(str2[i][j]+" ");
}
}
//函数
static void hanshu(int x,String y) {
String comp;
comp=y;
int k=0;
switch Fight

{
case 0:
for(int i=0;i<4;i++)
{
if(comp.equals(str1[i]))
str1[i]="*";
else
{ str2[0][k]=str1[i];
k++;
}
}
break;
}
}
}

5.Re:JAVA 魂牵梦绕的一道难题 [Re: jasonhero]	Copy to clipboard
Posted by: haiboxiaozi Posted on: 2006-05-21 15:16 好象有点难？看不懂，顶一下吧1

6.Re:JAVA 魂牵梦绕的一道难题 [Re: jasonhero]

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Posted by: qingzhipan027
Posted on: 2006-05-22 11:49

我改了下,语法上没什么问题了,可是好像执行不了……
import java.io.*;
public class t
{
static String str1[]={"A","B","C","D"};
static String str2[][]={{"*","*","*","*"},{"*","*","*","*"},{"*","*","*","*"},{"*","*","*","*"}};
public static void main(String args[])throws IOException
{

int bA;
String b1,b2,b3,b4,c1,c2,c3,c4;

BufferedReader aIn=new BufferedReader(new InputStreamReader(System.in));

//输入A
System.out.println("A说：");
b1=aIn.readLine();
bA=Integer.parseInt(b1);
c1=aIn.readLine();
String g = c1.substring(0,0);
hanshu(bA,g);//函数调用

System.out.println("B说：");
b2=aIn.readLine();
bA=Integer.parseInt(b2);
c2=aIn.readLine();
String g2 = c2.substring(0,0);
hanshu(bA,g2);//函数调用

System.out.println("C说：");
b3=aIn.readLine();
bA=Integer.parseInt(b3);
c3=aIn.readLine();
String g3 = c3.substring(0,0);
hanshu(bA,g3);//函数调用

System.out.println("D说：");
b4=aIn.readLine();
bA=Integer.parseInt(b4);
c4=aIn.readLine();
String g4 = c4.substring(0,0);
hanshu(bA,g4);//函数调用

//bA和c的输出
System.out.println(bA);
System.out.println();

//数组输出
for(int i=0;i<4;i++)
System.out.print(str1[i]+" ");
System.out.println("\n");
for(int i=0;i<4;i++)
{
System.out.println("\n");
for(int j=0;j<4;j++)
System.out.print(str2[i][j]+" ");
}
}
//函数
static void hanshu(int x,String y) {
String comp;
comp=y;
int k=0;
switch(x)
{
case 0:
for(int i=0;i<4;i++)
{
if(comp.equals(str1[i]))
str2[k][i]="*";
else
str2[k][i]=str1[i];
}
k++;
break;
case 1:
for(int i=0;i<4;i++)
{
if(comp.equals(str1[i]))
str2[k][i]=str1[i];
else
str2[k][i]="*";
}
k++;
break;
}
}
}