Java开发网 - 如何理解执行的先后顺序

Topic: 如何理解执行的先后顺序

1.如何理解执行的先后顺序

Posted by: 一枝梅
Posted on: 2005-06-08 11:46

class CCircle
{
double pi=3.14;
double radius;

void show_area(){
System.out.println("area="+pi*radius*radius);
}
void show_all(){
System.out.println("radius="+radius);
show_area();
}
}
public class ex4
{
public static void main(String args[])
{
CCircle cir1=new CCircle();
cir1.radius=2.0;
cir1.show_all();
}
}
运行结果是：
radius=2.0
area=12.56
为什么不反过来哟？

2.Re:如何理解执行的先后顺序 [Re: 一枝梅]

Copy to clipboard

Posted by: why
Posted on: 2005-06-08 12:07

Why should it 反过来???

cir1.show_all(); is called

System.out.println("radius="+radius); is executed
show_area(); is called

System.out.println("area="+pi*radius*radius); is excuted
return to show_all

return to main

sigh... please use a debugger...
I should have pointed to a section of the Java spec, but I don't think you would read it, so...

3.Re:如何理解执行的先后顺序 [Re: 一枝梅]	Copy to clipboard
Posted by: jfs771 Posted on: 2005-06-10 15:23 呵呵