Java开发网 - 哪位大哥帮忙多谢了 (输入整数n, 计算e=1/0!+...+1/n!))

Topic: 哪位大哥帮忙多谢了 (输入整数n, 计算e=1/0!+...+1/n!))

1.哪位大哥帮忙多谢了 (输入整数n, 计算e=1/0!+...+1/n!))	Copy to clipboard
Posted by: zidane2000 Posted on: 2004-09-17 00:30 编写一个Java Application程序，接受用户输入的一个整数n，计算e=1+1/1!+1/2!+1/3!+1/4!+…+1/n!，（检查1/n!<1E-5、考虑利用上一道题的代码）

2.Re:哪位大哥帮忙多谢了 [Re: zidane2000]

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Posted by: why
Posted on: 2004-09-17 02:45

考虑利用上一道题的代码？哪道题？请你为人设想一点儿，好吗？
阁下在请教他人喔。
唉──

I don't know what the requirement of 接受用户输入 is, but this is what I write for http://www.cjsdn.net/post/view?bid=1&id=110544
you may use a method for the calculation part and develop the proper "接受用户输入"

public class E {
  public static void main(String[] args) {
    int n = Integer.parseInt(args[0]);
    double delta = Double.parseDouble(args[1]);

    double iFactorial = 1.0;
    double sum = 1.0;
    for (int i=1; i<=n; i++) {
      iFactorial = iFactorial / (double)i;
      if (iFactorial < delta) {
        break;
      } else {
        sum = sum + iFactorial;
      }
    }
    System.out.println("E = " + sum);
    System.out.println("Math.E = " + Math.E);
    System.out.println("Diff = " + (Math.E - sum));
  }
}

3.Re:哪位大哥帮忙多谢了 (输入整数n, 计算e=1/0!+...+1/n!)) [Re: zidane2000]

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Posted by: eric_dasini
Posted on: 2004-09-17 14:29

public class test{
  public static void main(String []args){
    System.out.println(new test().operation(3));
  }

  double operation(int n){
    double fenmu = 1;
    double fenzi = 1;
    double sum = 1;

    for(int i=1; i<n+1; i++){
      for(int j=1; j<i+1; j++){
        fenmu = fenmu*j;
      }

      sum = sum + fenzi/fenmu;
    }

    return sum;
  }
}

判断自己添吧!!!

Topic: 哪位大哥帮忙 多谢了 (输入整数n, 计算e=1/0!+...+1/n!))

Topic: 哪位大哥帮忙多谢了 (输入整数n, 计算e=1/0!+...+1/n!))